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15x^2-65x+20=0
a = 15; b = -65; c = +20;
Δ = b2-4ac
Δ = -652-4·15·20
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-55}{2*15}=\frac{10}{30} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+55}{2*15}=\frac{120}{30} =4 $
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